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C++问题,把下列求解一元二次方程编程改写为返回结构体类型

#include<iostream>#include<cmath> using namespace std; class QEquation{ double a,b,c; public: QEquation(double x=1, double y=0, double z=-1){ a=x; b=y; c=z; } void set_coef(double x, double y, double z){ a=x; b=y; c=z; } void solve_equation(){

#include<math.h>#include <iostream>#include <sstream>#include <string>#include <cstdlib> using namespace std; std::string ConvertToString(float a); class M{ private: float A; float B; float C; public: M(); Assignment(float a,float b,float c); X(); }; M::

#include<iostream.h> #include<math.h> class Equation{ float a,b,c; public: float x[2]; Equation(float a1=0.0,float b1=0.0,float c1=0.0) { a=a1; b=b1; c=c1; } ~Equation(){} long CalResult(); }; long Equation::CalResult() { long temp; if ((b*b-4*a*c)

#include#include#includeusing namespace std;//一元一次方程:ax+b=0int main(){ float a,b,x; cin >>a>>b; x=-(b/a); //主意a不能为0 cout 评论0 0 0

已调试,无错误.希望对你有所帮助!#include<iostream.h> #include<math.h> void main() { double a,b,c,d,e,x1,x2; cout<<"请输入要求解的一元二次方程:"<<endl; cout<<"a: "; cin>>a; cout<<"b: "; cin>>b; cout<<"c: "; cin>>c; cout<<a

程序运行过了,没有问题,记得给分#include<iostream.h>#include<math.h> class Equation{ float a,b,c; public: float x[2]; Equation(float a1=0.0,float b1=0.0,float c1=0.0) { a=a1; b=b1; c=c1; } ~Equation(){} long CalResult(); }; long Equation::CalResult

#include<iostream>#include<math.h> // 开方时要用到using std::cout;using std::cin;using std::endl;#define _TCHAR char#define _tmain main#define OK 0;// 定义RootResult结构体为方程的解struct RootResult{ double x1; double x2; double derta;

g++version 4.4.3编译运行通过!~#include <iostream>#include <cmath>using namespace std;int main(){ float a,b,c,d,x1,x2,rpart,ipart; cout<<"方程为a*x^2+b*x+c=0,请输入a、b、c的值"<<endl; cin>>a>>b>>c; if (a==0) { if (b==0) cout<<"方程

//解一元二次方程的C++程序 #include<iostream.h> #include<math.h> #include<iomanip.h> void sqrt1(double,double); void sqrt2(double,double); void printer(double,double); void main() { float a,b,c; double x1,x2; cout<<"请输入a,b,c:"<<endl; cin

结构化编程方法://for two roots#include <iostream.h>#include <math.h>int main(){ double a,b,c,rp,ip;//方程系数 double x1,x2;//方程的根 double d;//根的判别式 cout<<"input a,b,c(方程系数):"; cin>>a>>b>>c; if(a==0) cout<<"这不是二

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